Replace array value to increment












3















I have an array like this ...



[0,0,23,0,0,18,0,0]


Then I want to change values ​​that are not '0' (23 & 18) to auto increment, so the end result will be like this,



[0,0,1,0,0,2,0,0]


is there the best way for all that?
So far this is what I did, but the results were not as expected ... :)



<?php

$arr = [0,0,23,0,0,18,0,0];
$x = 1;
$r = collect($arr)->map(function ($value, $key)use($x) {
if ($value == 0) {
return $value;
} else {
return $x++;
}
})->all();

dd($r);









share|improve this question

























  • What have you tried so far?

    – Nigel Ren
    Nov 13 '18 at 20:27











  • Show us some code!

    – Brogan
    Nov 13 '18 at 20:30











  • If you increment 23, does that not become 24?

    – Progrock
    Nov 13 '18 at 20:32











  • Out of curiosity... what's function collect?

    – dn Fer
    Nov 13 '18 at 21:08











  • @dnFer I think it's probably this.

    – Don't Panic
    Nov 13 '18 at 21:28
















3















I have an array like this ...



[0,0,23,0,0,18,0,0]


Then I want to change values ​​that are not '0' (23 & 18) to auto increment, so the end result will be like this,



[0,0,1,0,0,2,0,0]


is there the best way for all that?
So far this is what I did, but the results were not as expected ... :)



<?php

$arr = [0,0,23,0,0,18,0,0];
$x = 1;
$r = collect($arr)->map(function ($value, $key)use($x) {
if ($value == 0) {
return $value;
} else {
return $x++;
}
})->all();

dd($r);









share|improve this question

























  • What have you tried so far?

    – Nigel Ren
    Nov 13 '18 at 20:27











  • Show us some code!

    – Brogan
    Nov 13 '18 at 20:30











  • If you increment 23, does that not become 24?

    – Progrock
    Nov 13 '18 at 20:32











  • Out of curiosity... what's function collect?

    – dn Fer
    Nov 13 '18 at 21:08











  • @dnFer I think it's probably this.

    – Don't Panic
    Nov 13 '18 at 21:28














3












3








3








I have an array like this ...



[0,0,23,0,0,18,0,0]


Then I want to change values ​​that are not '0' (23 & 18) to auto increment, so the end result will be like this,



[0,0,1,0,0,2,0,0]


is there the best way for all that?
So far this is what I did, but the results were not as expected ... :)



<?php

$arr = [0,0,23,0,0,18,0,0];
$x = 1;
$r = collect($arr)->map(function ($value, $key)use($x) {
if ($value == 0) {
return $value;
} else {
return $x++;
}
})->all();

dd($r);









share|improve this question
















I have an array like this ...



[0,0,23,0,0,18,0,0]


Then I want to change values ​​that are not '0' (23 & 18) to auto increment, so the end result will be like this,



[0,0,1,0,0,2,0,0]


is there the best way for all that?
So far this is what I did, but the results were not as expected ... :)



<?php

$arr = [0,0,23,0,0,18,0,0];
$x = 1;
$r = collect($arr)->map(function ($value, $key)use($x) {
if ($value == 0) {
return $value;
} else {
return $x++;
}
})->all();

dd($r);






php arrays






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 21:30









Don't Panic

28.9k93856




28.9k93856










asked Nov 13 '18 at 20:27









Cristal TravelCristal Travel

383




383













  • What have you tried so far?

    – Nigel Ren
    Nov 13 '18 at 20:27











  • Show us some code!

    – Brogan
    Nov 13 '18 at 20:30











  • If you increment 23, does that not become 24?

    – Progrock
    Nov 13 '18 at 20:32











  • Out of curiosity... what's function collect?

    – dn Fer
    Nov 13 '18 at 21:08











  • @dnFer I think it's probably this.

    – Don't Panic
    Nov 13 '18 at 21:28



















  • What have you tried so far?

    – Nigel Ren
    Nov 13 '18 at 20:27











  • Show us some code!

    – Brogan
    Nov 13 '18 at 20:30











  • If you increment 23, does that not become 24?

    – Progrock
    Nov 13 '18 at 20:32











  • Out of curiosity... what's function collect?

    – dn Fer
    Nov 13 '18 at 21:08











  • @dnFer I think it's probably this.

    – Don't Panic
    Nov 13 '18 at 21:28

















What have you tried so far?

– Nigel Ren
Nov 13 '18 at 20:27





What have you tried so far?

– Nigel Ren
Nov 13 '18 at 20:27













Show us some code!

– Brogan
Nov 13 '18 at 20:30





Show us some code!

– Brogan
Nov 13 '18 at 20:30













If you increment 23, does that not become 24?

– Progrock
Nov 13 '18 at 20:32





If you increment 23, does that not become 24?

– Progrock
Nov 13 '18 at 20:32













Out of curiosity... what's function collect?

– dn Fer
Nov 13 '18 at 21:08





Out of curiosity... what's function collect?

– dn Fer
Nov 13 '18 at 21:08













@dnFer I think it's probably this.

– Don't Panic
Nov 13 '18 at 21:28





@dnFer I think it's probably this.

– Don't Panic
Nov 13 '18 at 21:28












2 Answers
2






active

oldest

votes


















3














The problem is that when you have your value of $x passed into the function via use, this isn't allowing the value to be updated. You need to pass it by reference - use (&$x) to allow it to increment the value outside the function...



$r = collect($arr)->map(function ($value, $key) use (&$x) {





share|improve this answer
























  • Thank you very much @Nigel, this really saved my day...

    – Cristal Travel
    Nov 13 '18 at 20:49



















0














Another way... Using foreach with reference of array &



With Passed by Reference



Snippet



$arr = [0,0,23,0,0,18,0,0];
$counter = 1;
foreach ($arr as &$val){
if($val !== 0){
$val = $counter++;
}
}
print_r($arr);


Note: Be aware of dangling reference




Without reference



Snippet



$arr = [0,0,23,0,0,18,0,0];
$counter = 1;
foreach ($arr as $key => $val){
if($val !== 0){
$arr[$key] = $counter++;
}
}
print_r($arr);


Output



Array
(
[0] => 0
[1] => 0
[2] => 1
[3] => 0
[4] => 0
[5] => 2
[6] => 0
[7] => 0
)


Live demo

Pass by reference docs






share|improve this answer


























  • $val = $counter++; or $val = ++$counter; saves you a line of code. ;)

    – dn Fer
    Nov 13 '18 at 21:13











  • @dnFer error occurred

    – Smartpal
    Nov 13 '18 at 21:26











  • Not when I change your demo.

    – dn Fer
    Nov 13 '18 at 21:30











  • @dnFer Link modified demo

    – Smartpal
    Nov 13 '18 at 21:33











  • 3v4l.org/eIEhe

    – dn Fer
    Nov 13 '18 at 21:41











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














The problem is that when you have your value of $x passed into the function via use, this isn't allowing the value to be updated. You need to pass it by reference - use (&$x) to allow it to increment the value outside the function...



$r = collect($arr)->map(function ($value, $key) use (&$x) {





share|improve this answer
























  • Thank you very much @Nigel, this really saved my day...

    – Cristal Travel
    Nov 13 '18 at 20:49
















3














The problem is that when you have your value of $x passed into the function via use, this isn't allowing the value to be updated. You need to pass it by reference - use (&$x) to allow it to increment the value outside the function...



$r = collect($arr)->map(function ($value, $key) use (&$x) {





share|improve this answer
























  • Thank you very much @Nigel, this really saved my day...

    – Cristal Travel
    Nov 13 '18 at 20:49














3












3








3







The problem is that when you have your value of $x passed into the function via use, this isn't allowing the value to be updated. You need to pass it by reference - use (&$x) to allow it to increment the value outside the function...



$r = collect($arr)->map(function ($value, $key) use (&$x) {





share|improve this answer













The problem is that when you have your value of $x passed into the function via use, this isn't allowing the value to be updated. You need to pass it by reference - use (&$x) to allow it to increment the value outside the function...



$r = collect($arr)->map(function ($value, $key) use (&$x) {






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 13 '18 at 20:43









Nigel RenNigel Ren

27.2k61833




27.2k61833













  • Thank you very much @Nigel, this really saved my day...

    – Cristal Travel
    Nov 13 '18 at 20:49



















  • Thank you very much @Nigel, this really saved my day...

    – Cristal Travel
    Nov 13 '18 at 20:49

















Thank you very much @Nigel, this really saved my day...

– Cristal Travel
Nov 13 '18 at 20:49





Thank you very much @Nigel, this really saved my day...

– Cristal Travel
Nov 13 '18 at 20:49













0














Another way... Using foreach with reference of array &



With Passed by Reference



Snippet



$arr = [0,0,23,0,0,18,0,0];
$counter = 1;
foreach ($arr as &$val){
if($val !== 0){
$val = $counter++;
}
}
print_r($arr);


Note: Be aware of dangling reference




Without reference



Snippet



$arr = [0,0,23,0,0,18,0,0];
$counter = 1;
foreach ($arr as $key => $val){
if($val !== 0){
$arr[$key] = $counter++;
}
}
print_r($arr);


Output



Array
(
[0] => 0
[1] => 0
[2] => 1
[3] => 0
[4] => 0
[5] => 2
[6] => 0
[7] => 0
)


Live demo

Pass by reference docs






share|improve this answer


























  • $val = $counter++; or $val = ++$counter; saves you a line of code. ;)

    – dn Fer
    Nov 13 '18 at 21:13











  • @dnFer error occurred

    – Smartpal
    Nov 13 '18 at 21:26











  • Not when I change your demo.

    – dn Fer
    Nov 13 '18 at 21:30











  • @dnFer Link modified demo

    – Smartpal
    Nov 13 '18 at 21:33











  • 3v4l.org/eIEhe

    – dn Fer
    Nov 13 '18 at 21:41
















0














Another way... Using foreach with reference of array &



With Passed by Reference



Snippet



$arr = [0,0,23,0,0,18,0,0];
$counter = 1;
foreach ($arr as &$val){
if($val !== 0){
$val = $counter++;
}
}
print_r($arr);


Note: Be aware of dangling reference




Without reference



Snippet



$arr = [0,0,23,0,0,18,0,0];
$counter = 1;
foreach ($arr as $key => $val){
if($val !== 0){
$arr[$key] = $counter++;
}
}
print_r($arr);


Output



Array
(
[0] => 0
[1] => 0
[2] => 1
[3] => 0
[4] => 0
[5] => 2
[6] => 0
[7] => 0
)


Live demo

Pass by reference docs






share|improve this answer


























  • $val = $counter++; or $val = ++$counter; saves you a line of code. ;)

    – dn Fer
    Nov 13 '18 at 21:13











  • @dnFer error occurred

    – Smartpal
    Nov 13 '18 at 21:26











  • Not when I change your demo.

    – dn Fer
    Nov 13 '18 at 21:30











  • @dnFer Link modified demo

    – Smartpal
    Nov 13 '18 at 21:33











  • 3v4l.org/eIEhe

    – dn Fer
    Nov 13 '18 at 21:41














0












0








0







Another way... Using foreach with reference of array &



With Passed by Reference



Snippet



$arr = [0,0,23,0,0,18,0,0];
$counter = 1;
foreach ($arr as &$val){
if($val !== 0){
$val = $counter++;
}
}
print_r($arr);


Note: Be aware of dangling reference




Without reference



Snippet



$arr = [0,0,23,0,0,18,0,0];
$counter = 1;
foreach ($arr as $key => $val){
if($val !== 0){
$arr[$key] = $counter++;
}
}
print_r($arr);


Output



Array
(
[0] => 0
[1] => 0
[2] => 1
[3] => 0
[4] => 0
[5] => 2
[6] => 0
[7] => 0
)


Live demo

Pass by reference docs






share|improve this answer















Another way... Using foreach with reference of array &



With Passed by Reference



Snippet



$arr = [0,0,23,0,0,18,0,0];
$counter = 1;
foreach ($arr as &$val){
if($val !== 0){
$val = $counter++;
}
}
print_r($arr);


Note: Be aware of dangling reference




Without reference



Snippet



$arr = [0,0,23,0,0,18,0,0];
$counter = 1;
foreach ($arr as $key => $val){
if($val !== 0){
$arr[$key] = $counter++;
}
}
print_r($arr);


Output



Array
(
[0] => 0
[1] => 0
[2] => 1
[3] => 0
[4] => 0
[5] => 2
[6] => 0
[7] => 0
)


Live demo

Pass by reference docs







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 14 '18 at 9:21

























answered Nov 13 '18 at 20:51









SmartpalSmartpal

962516




962516













  • $val = $counter++; or $val = ++$counter; saves you a line of code. ;)

    – dn Fer
    Nov 13 '18 at 21:13











  • @dnFer error occurred

    – Smartpal
    Nov 13 '18 at 21:26











  • Not when I change your demo.

    – dn Fer
    Nov 13 '18 at 21:30











  • @dnFer Link modified demo

    – Smartpal
    Nov 13 '18 at 21:33











  • 3v4l.org/eIEhe

    – dn Fer
    Nov 13 '18 at 21:41



















  • $val = $counter++; or $val = ++$counter; saves you a line of code. ;)

    – dn Fer
    Nov 13 '18 at 21:13











  • @dnFer error occurred

    – Smartpal
    Nov 13 '18 at 21:26











  • Not when I change your demo.

    – dn Fer
    Nov 13 '18 at 21:30











  • @dnFer Link modified demo

    – Smartpal
    Nov 13 '18 at 21:33











  • 3v4l.org/eIEhe

    – dn Fer
    Nov 13 '18 at 21:41

















$val = $counter++; or $val = ++$counter; saves you a line of code. ;)

– dn Fer
Nov 13 '18 at 21:13





$val = $counter++; or $val = ++$counter; saves you a line of code. ;)

– dn Fer
Nov 13 '18 at 21:13













@dnFer error occurred

– Smartpal
Nov 13 '18 at 21:26





@dnFer error occurred

– Smartpal
Nov 13 '18 at 21:26













Not when I change your demo.

– dn Fer
Nov 13 '18 at 21:30





Not when I change your demo.

– dn Fer
Nov 13 '18 at 21:30













@dnFer Link modified demo

– Smartpal
Nov 13 '18 at 21:33





@dnFer Link modified demo

– Smartpal
Nov 13 '18 at 21:33













3v4l.org/eIEhe

– dn Fer
Nov 13 '18 at 21:41





3v4l.org/eIEhe

– dn Fer
Nov 13 '18 at 21:41


















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